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(A) The enthalpy of hydrogenation is inversely proportional to the stability of the alkene.Stability of alkenes is determined by the number of $\alpha

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$II > III > I$

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(A) The enthalpy of hydrogenation is inversely proportional to the stability of the alkene.Stability of alkenes is determined by the number of $\alpha$-hydrogens (hyperconjugation).Compound $I$ is a tetrasubstituted alkene with $8$ $\alpha$-hydrogens.Compound $III$ is a trisubstituted alkene with $5$ $\alpha$-hydrogens.Compound $II$ is a disubstituted alkene with $4$ $\alpha$-hydrogens.Since stability order is $I > III > II$,the enthalpy of hydrogenation order is $II > III > I$.

Given the enthalpy of hydrogenation of these compounds will be in the order:

Similar Questions

Classify the types of chemical reactions that alkenes undergo and provide examples for each.

The compounds that will give an isomer of $2,2$-dimethylpropane on catalytic hydrogenation are:
$(1)$ $CH_3-CH=C(CH_3)_2$
$(2)$ $CH_3-CH=CH-CH_3$
$(3)$ $CH_3-CH=CH-CH_2-CH_3$
$(4)$ $CH_3-C(CH_3)=C(CH_3)-CH_3$

What will be the product $B$ formed in the following reaction sequence?
$CH_3CH_2CH_2OH$ $\xrightarrow{PCl_5} A$ $\xrightarrow{alc. KOH} B$

Identify the product $C$ in the following reaction sequence:
$CH_3CH_2C \equiv CH + HCl \to B \xrightarrow{HI} C$

The reaction $R-CH=CH_2 \xrightarrow{Na/NH_3, C_2H_5OH} R-CH_2CH_3$ is known as:

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